What is the median class? Ans. The class where cumulative frequency first exceeds ( N/2 ).
( N = 35 ), ( N/2 = 17.5 ) → Median class = 20-30 ( L = 20, cf = 13, f = 12, h = 10 ) Median = ( 20 + \frac17.5 - 1312 \times 10 = 20 + 3.75 = 23.75 ) Example 3: Mode – Continuous Series | Class | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 | |-------|------|-------|-------|-------|-------| | f | 4 | 9 | 15 | 8 | 2 |
Write the empirical formula for mode. Ans. Mode = 3 Median – 2 Mean
Modal class = 20-30 (( f_1 = 15 )) ( L = 20, f_0 = 9, f_2 = 8, h = 10 ) Mode = ( 20 + \frac15 - 92\times15 - 9 - 8 \times 10 = 20 + \frac613 \times 10 ) = ( 20 + 4.615 = 24.615 ) 4. Important Short Answer Questions (as per Sandeep Garg) Q1. When is median preferred over mean? Ans. – Open-ended classes, skewed distribution, ordinal data, presence of extreme values.
Statistics For Economics Class 11 Sandeep Garg Solutions Chapter 9 ((top)) | Genuine & Certified
What is the median class? Ans. The class where cumulative frequency first exceeds ( N/2 ).
( N = 35 ), ( N/2 = 17.5 ) → Median class = 20-30 ( L = 20, cf = 13, f = 12, h = 10 ) Median = ( 20 + \frac17.5 - 1312 \times 10 = 20 + 3.75 = 23.75 ) Example 3: Mode – Continuous Series | Class | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 | |-------|------|-------|-------|-------|-------| | f | 4 | 9 | 15 | 8 | 2 | What is the median class
Write the empirical formula for mode. Ans. Mode = 3 Median – 2 Mean ( N = 35 ), ( N/2 = 17
Modal class = 20-30 (( f_1 = 15 )) ( L = 20, f_0 = 9, f_2 = 8, h = 10 ) Mode = ( 20 + \frac15 - 92\times15 - 9 - 8 \times 10 = 20 + \frac613 \times 10 ) = ( 20 + 4.615 = 24.615 ) 4. Important Short Answer Questions (as per Sandeep Garg) Q1. When is median preferred over mean? Ans. – Open-ended classes, skewed distribution, ordinal data, presence of extreme values. Important Short Answer Questions (as per Sandeep Garg) Q1